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Geometric Series Question
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How could this be equal? If we simplify it, it would be 1200(1-(1.03)^n-1) = 3600(1-(1.03)^n-1) 1200 =/= 3600
Let me call someone.. @lgbasallote
i dont get the question lol...sorry
but my explanation above showing that the system would never be equal is right, right?
I am also given other information. The fixed cost of one system is $10,000 and the yearly costs of that system are \[T _{n} = 3600(1.03)^{n}\]
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Have no idea, sorry :/
Okay and one system is The fixed cost is $50,000 and the yearly costs of that system are: \[T _{n}=1200(1.03)^{n}\]
My question is Determine an equation that could be solved to determine the number of years when the cost of each system is Equivalent.
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