Geometric Series Question

Question

zepp · Answer

How could this be equal?
If we simplify it, it would be 1200(1-(1.03)^n-1) = 3600(1-(1.03)^n-1)
1200 =/= 3600

zepp · Answer

Let me call someone.. @lgbasallote

lgbasallote · Answer

i dont get the question lol...sorry

zepp · Answer

but my explanation above showing that the system would never be equal is right, right?

anonymous · Answer

I am also given other information. The fixed cost of one system is $10,000 and the yearly costs of that system are
$$T _{n} = 3600(1.03)^{n}$$

zepp · Answer

Have no idea, sorry :/

anonymous · Answer

Okay and one system is
The fixed cost is $50,000 and the yearly costs of that system are:

$$T _{n}=1200(1.03)^{n}$$

anonymous · Answer

My question is Determine an equation that could be solved to determine the number of years when the cost of each system is Equivalent.