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perform the division 19x^7+6x^3/x
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@campbell_st u take over
write it as the sum of 2 fractions \[\frac{19x^7}{x} + \frac{6x^3}{x}\] index law for division is subtract the powers \[19x^{7-1} + 6x^{3-1} = 19x^6 + 6x^2\]
19x^6+6x^2
is that how
thats it
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@bh104 camp is correct
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