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OpenStudy (anonymous):
a^2-64-16a factor completely
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jhonyy9 (jhonyy9):
(a-8)(a+8)-16a
jhonyy9 (jhonyy9):
a_1,2=(16+/-sqrt512)/2 =(16+/- 16sqrt2)/2 = 8+/- 8sqrt2 - so after this factored completly will be : (a-8-8sqrt2)(a-8+8sqrt2)
OpenStudy (anonymous):
would it just be (a-8^2)(a+8^2)?
jhonyy9 (jhonyy9):
no - is how i have wrote there
jhonyy9 (jhonyy9):
sqrt2 is squareroot of 2
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OpenStudy (anonymous):
k
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