Question

line segment CD is perpendicular to line segment AB at E. Point F is in the interior of angle CEB. the measure of angle CEF is 8 times the measure of angle FEB. find angle FEB.

Answer 1

that's much better. try thinking of the sum of the angles CEF and CEB equal to 90

Answer 2

so its 8x+8=90???

Answer 3

try 8x + x = 90

Answer 4

oh..

Answer 5

=10

Answer 6

angle CEF is 8 times FEB. (i just realized I should have said CEF and FEB)

Answer 7

10 degrees sounds right.

Answer 8

do you understand how the equation was set up?

Answer 9

then where is point F??

Answer 10

oh.... ok THX

Answer 11

obviously I did not do a very good job of representing angle FEB of being only 10 degrees

Answer 12

THX

Answer 13

sure, you are welcome