Two electric bulbs whose resistances are in the ratio of 1 : 2 are connected in parallel to a constant voltage source. The powers dissipated in them have the ratio.

a
1 : 2

b
1 : 1

c
2 : 1

d
1 : 4

Question

Two electric bulbs whose resistances are in the ratio of 1 : 2 are connected in parallel to a constant voltage source. The powers dissipated in them have the ratio.

a	
     1 : 2

b	
     1 : 1

c	
     2 : 1

d	
     1 : 4

anonymous · Answer

Using I*V=p

we know that in a parallel circuit the voltage is always the same but the current is different

if we use I=V/R and take for example a 4ohm resistor and and 8 ohm resistor, lets say the voltage is 3 volts

I=3/4
I=.75 amps

I=3/8
I=.375amps

So if we plug it back into the equation I*V=p

(.375)*3=1.125

(.75)*3=2.25

you can now see that it is a 2:1 relationship