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Mathematics 21 Online
OpenStudy (anonymous):

factor completely 3w^2-243

OpenStudy (anonymous):

i got w^2+8

jimthompson5910 (jim_thompson5910):

3w^2-243 3(w^2-81) 3(w^2-9^2) 3(w-9)(w+9) So 3w^2-243 completely factors to 3(w-9)(w+9)

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