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Solve. Round your answer to three decimal places 4^x+1=6^x-1
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|dw:1335727857725:dw|
take the log of both sides\[\log \left( 4^{x+1} \right) = \log \left( 6^{x-1} \right)\]and then solve for x by using algebra and properties of logarithms
well i got x = 1 then what do i do ?
These are the answer choices.. A. .128 B..200 C. 7.838 D. 5.00
how did you get 1 ?
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through the calculator :/
recheck your work, the answer is C
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