Question

2x2 – 8x – 16 = 0

Answer 1

2x^2

Answer 2

\[
\begin{align}
2x^2-8x-16&=0\\
2(x^2-4x+4)-24&=0\\
2(x-2)^2-24&=0\\
(x-2)^2&=12\\
x-2&=\pm\sqrt{12}\\
x&=2\pm2\sqrt{3}
\end{align}
\]