Question

Solve the equation?
√4x - 3 = x

Answer 1

\[\sqrt{4x}=x+3\]

Answer 2

square both sides.\[4x=x ^{2}+6x+9\]

Answer 3

√4x = x +3
4x =(x+3)^2
4x=x^2+6x+9
x^2+2x+9=0
has no real solutions

Answer 4

Last one .. Can someone answer it?
√x - 6 + 4 = 9

Answer 5

what's under the sqrt?

Answer 6

only x?

Answer 7

Yes.

Answer 8

√x = 11

Answer 9

x=121

Answer 10

I checked Pre.CalSolved and it said 121 ... Wouldn't the sq root of that be 11?

Answer 11

Consolidate terms\[x ^{2}+2x+9=0\]
x= \[-2\pm \sqrt{4-4(9)}\over 2\]\[-2\pm \sqrt{-32}\over2\]\[-2\pm4\sqrt{-2}\over2\]\[-1\pm2\sqrt{2}i \]

Answer 12

yes

Answer 13

Provided the problem was as I copied