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OpenStudy (anonymous):
(ab^2)^-2 simplify
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OpenStudy (anonymous):
1 / (a * b²)²
OpenStudy (henryblah):
Any negative powers mean 1 over. So it would be \[1/(ab^2)^2\]
OpenStudy (anonymous):
or: a^( -2 ) * b^( -4) = 1/a² * 1/b^(4)
OpenStudy (precal):
|dw:1335736267727:dw|
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