Question

The height of a parallelogram is 10 feet more than its base. If the area of the parallelogram is 120 square feet, find it's base and height.

How would I set this up, and solve?

Answer 1

area of a parallelogram = (base)(height)

base = x
height = x + 10
area = 120

x(x +10)=120

Answer 2

x(x + 10) = 120

x(x + 10) -120 = 0
\[x ^{2} + 10x -120 = 0\]
now us the quadratic equation
\[(-b \pm \sqrt{b ^{2} - 4ac})/(2a)\]