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OpenStudy (anonymous):
3 cos ^ 2 theta - 5 cos theta - 1 - 3 sin ^ 2 theta = 0 3 cos ^ 2 theta - 5 cos theta - 1 - 3 ( 1 - cos ^ 2 theta ) = 0 3 cos ^ 2 theta - 5 cos theta - 1 - 3 + 3 cos ^ 2 theta = 0 6 cos ^ 2 theta - 5 cos theta - 4 = 0 Substitute : u = cos theta 6 u ^ 2 - 5 u - 4 = 0 The exact solutons are : u = cos teta = 4 / 3 = 1.333 and u = cos theta = - 1 / 2 cosine can't be great of 1 so the solutions are : cos theta = - 1 / 2 theta = ( 2 / 3 ) pi = 120 � and theta = ( 4 / 3 ) pi = 240
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OpenStudy (campbell_st):
looks correct to me
OpenStudy (anonymous):
thanx!
OpenStudy (anonymous):
@lgbasallote can u find the ans of this^^
OpenStudy (lgbasallote):
seems right to me too...
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