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L is the midpoint of CD. If 1 over 3 x+8 and LD= 2 over 3 x -4, find the length of CD
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...@Eric_Playsinacoolway lol
@Kreshnik can you help her!
double the equation = CD
fist ... let's draw something:P |dw:1335779209277:dw| now length of CD is length of CL and LD from given: \[\LARGE CL=\frac13x+8\] and \[\LARGE LD=\frac23 x-4\] we have: \[\LARGE CL+LD=CD\]
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