Question

give exact value for: ln(e^2)-log base3.7 1+log base6 9+log base6 4-log10

Answer 1

\[\Large \ln(e^2)-\log_{3.7}(1)+\log_6(9)+\log_{6}(4)-\log(10)=\]
\[\Large 2\ln(e)-0+\log_6(9)+\log_{6}(4)-1=\]
\[\Large 2\cdot 1+\log_6(9\cdot 4)-1=\]
\[\Large 2+\log_6(36)-1=\]
\[\Large 1+\log_6(6^2)=\]
\[\Large 1+2\cdot \log_6(6)=\]
\[\Large 1+2\cdot 1=3\]

Answer 2

do you know log rules ?

Answer 3

i am just learning them. kind of pushed on us at the end of semester and not alot of time to spend on learning them. thank you for the help. i usually learn better if i can see the problem worked out first.

Answer 4

Glad to help :)

Answer 5

TY