Question

what are the approximate solutions of 2x^2-x+10=0? f) -2,2.5 g) -1.97,2.47 h)-2.5,2 i) no solution. help me please. :*

Answer 1

do you know the quadratic formula?

Answer 2

yeah but i don't know how to use it on a question like this. :(

Answer 3

ok ... let's give it a try ;)
\[\LARGE {x_{1/2}} = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]


\[\LARGE \Delta=b^2-4ac\]
if
\[\LARGE \Delta>0 \;\;two \;\;solutions\]
\[\LARGE \Delta=0 \;\;one \;\;solution\]
\[\LARGE \Delta<0 \;\;no\;\;solution \]

Answer 4

now... applying the given ... we get:
\[\LARGE {x_{1/2}} = \frac{{ - 1 \pm \sqrt {1 - 4 \cdot 20} }}{{2a}}\]
from here we see that expression under square root will be negative...
and therefore it has no solution... :)

Answer 5

so the answer is i) no solution

Answer 6

omg, thank youuuu. i'll have other questions up about this cause i'm like totally lost, but thank you so much. <3

Answer 7

where are you stucked? ... post it on wall. (not here) so other members can help you, (If I don't know it) .. :)