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Mathematics 11 Online
OpenStudy (anonymous):

Lim sin x/x ? x ->0

OpenStudy (inkyvoyd):

Google it for an explanation, because there are quite a few, and quite good explanations on google

OpenStudy (anonymous):

do you have to proof it?

OpenStudy (anonymous):

yes I have to prove it

OpenStudy (anonymous):

for DETAIL click khan academy... http://znd-search-test.khan-academy.appspot.com/math/calculus/v/proof--lim--sin-x--x

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