Question

Help please! <3

Answer 1

In attachment ^^

Answer 2

what you can get in common in numerator?

Answer 3

Do I divide 4 by 8,12,16 ?

Answer 4

\[\LARGE \frac{8x^2y+12xy^3-16xy}{4xy}={4xy(?+?-?)\over 4xy}\]

Answer 5

so 4xy would cancel out... what has left?? :)

Answer 6

2x + 3y^2 - 4 <-- is this my answer?

Answer 7

@Kreshnik

Answer 8

yes it is... well done ;)

Answer 9

Thank you! :)

Answer 10

My pleasure xD