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the square of a number is 8 smaller than the product of the number and its successor. what is the number, please show in an equation too.
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do you know what it is?
try starting by using x as the number they are describing.
i know. i did x^2
okay. and the answer is 8, i just don't have an equation.
\[x ^{2}=(x)(x+1)-8\]
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okay. i had \[x^2 = 8-x*(x+1)\]
does that work?
no
why not?
the number squared is 8 LESS than the the product of the two.
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pg stated it correctly \[x^{2}=x ^{2}+x-8; so 0=x-8 ; so x=8\]
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