Question

What is the magnitude of the force on an electron moving with a velocity of 6.33 × 106 m/s at right angles to a 2.53 × 10-2 T magnetic field?
2.56 × 10-14 N
2.56 × 10-11 N
2.56 × 10-8 N
2.56 × 10-5 N
2.56 × 10-2 N

Answer 1

F= e(V x B) = eVB sin theta...

Answer 2

e = ??
theta =??
B=2.53 × 10-2 T ??

Answer 3

e is electronic charge. theta is angle between velocity of electron and magnetic field.. B is magnetic field.

Answer 4

theta will be 180 ?
e =1.602×10^-19 ????

Answer 5

2.56 x 10^-14

Answer 6

1 ans is correct