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2x^2-5x-3=0
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ok first you need to multiply 2 and -3
right! multiply a*c then what?
that becomes -6 so then you need two numbers that equal -5
1 & -5
no 2,-3
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Oh okay.
(x+2)(x-3) = 0
2x^2+2x-3x-3
then split them up
Split what up?
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its kinda hard to explain
:/
well I failed ..
here 2x(x-3) 2(x-3)
ohhhh i see
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(2x-2) (x-3)
its suppose to be -2 and -3
something like that sorry
then set them to 0
k
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2x-2=0 x-3=0
2x=2 x=3
x= 1 X
right{1,3}
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