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how high is the kite off the ground Red is kite ill post image
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\[\tan \theta=opposite/adjacent\] You know that the side adjacent to the angle of 50 degrees is 160 units long so plug that in and solve for the opposite value.
can you show
\[\tan \theta = opposite/adjacent\] \[\tan 50 = opposite/160\] \[(\tan50)(160)=opposite\] Plug that into the calculator to solve for the opposite value.
dont have a calc like tht
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still confused
190.68
Yeah
tht it?
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Yep
tnx
No problem
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