Question

(3+a^-1)^-1

Answer 1

help

Answer 2

\[(3+a^{-1})=3+\frac{1}{a}=\frac{3a+1}{a}\]

Answer 3

and therefore
\[(3+a^{-1})^{-1}=\frac{a}{3a+1}\]

Answer 4

thanks

Answer 5

yw