Question

how to evaluate the integral.... (cos (sqrt x)) / (sqrt x)

Answer 1

try \(u=\sqrt{x}, du=\frac{1}{2\sqrt{x}}, 2du=\frac{1}{\sqrt{x}}dx\)

Answer 2

and so you have
\[2\int\cos(u)du\]

Answer 3

i assume by "evaluate" you mean find the anti derivative

Answer 4

\[evaluated the interval \int\limits_{}^{} x/(x-1)^{3}dx\]