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Find the area of a section of a circle which has 8" radius if the sector has an arc that measures 45°. _____ times pi sq. in.
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Area of sector is \[1/2 \times r ^{2}\times \theta\]
if area = pi r2, then 16 * 16* 256, 804, now lets cut this circle into eight pieces, like this, they are cut into 8 pieces with 2 45, circumference lines, in a manner we can say that 804/8 will give you your answer, which is 100.5
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That is what you where asking for, am I correct?
Area of sector is:\[((\pi \times r ^{2})\div360)\times45=25.13\square inches\]
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Thanks everyone [:
I hope I was right, correct me if im not, and as always, my plesure :D
The correct form of the answer is : \[8\times\pi) squareinches\]
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