Question

find indefinite integral
(t^8/8 + 1/4t^7)dt
...
(x^2+2)e^((x^3)+6x
..
(x+9)/sqrt (36-(x-6)^2)

Answer 1

\[\int\limits_{}^{}((t ^{8}+1/(4t ^{7}))dt=t ^{9}/72-1/(24t ^{6})+C\]

Answer 2

Is the second expression:
\[(x ^{2}+2)(e ^{x ^{3}})+6x\]