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Mathematics 11 Online
OpenStudy (boxman61):

solve: log(2x+20)=1

OpenStudy (anonymous):

2x+20=10

OpenStudy (eyust707):

When you see that you should read it in your head as: "10 to the power of 1 equals (2x+20)"

OpenStudy (boxman61):

x=-5.... thanks

OpenStudy (anonymous):

log(2x+20)=1log10 2x+20=10 x=-5

OpenStudy (anonymous):

\[\text{Log}[20+2 x]=1 \]\[20+2 x=e\]\[x=\frac{1}{2} (e-20) \]

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