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Mathematics 20 Online
OpenStudy (raheelafzaal):

limit (x-->3)x^2-9/x-3=?

OpenStudy (anonymous):

(x^2 - 9) ----------- ...x - 3 Factor the numerator to (x + 3)(x - 3) (x + 3)(x - 3) ----------------- .....(x - 3) The x - 3 in the numerator cancels with the x - 3 in the denominator and you're left with x + 3 Now, just substitute 3 into the equation Lim (x - - > 3) x + 3 = 3 + 3 source: http://answers.yahoo.com/question/index?qid=20080430175035AA8GNh6

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