Question

derivation of sin^2x?

Answer 1

I'm just learning about this too. See if I answer this right.
Is it 2xsin^2x-1?

Answer 2

2sinxcosx am i right?

Answer 3

sin(A + B) = sin A cos B + cos A sin B

sin(2x) = sin(x + x) = sin x cos x + cos x sin x = 2 sin x cos x

SOURCE http://answers.yahoo.com/question/index?qid=20081116100909AA0li2n

Answer 4

Oh well.

Answer 5

its 2sinxcosx

Answer 6

thanks

Answer 7

\[\int\limits_{0}^{pi}cosxdx?\]

Answer 8

\[\int\limits_{0}^{pi/2}cosxdx?\]

Answer 9

well, when you integrate cosx its sinx. then you sub in the limits.

Answer 10

first integrate

integral of cosx=sinx

now put in the limits

sin(pie/2) - sin(0)=1 answer :D