Question

(X-3)^2+(Y+6)^2=25

Answer 1

circle centered at (3, -6) with radius r = 5

http://www.wolframalpha.com/input/?i=+%28x-3%29%5E2%2B%28y%2B6%29%5E2%3D25+

Answer 2

ok well u dont have to use wolfram for this its pretty simple.
the equation of a cricle is x^2+y^2=r^2
So from this equation we know that the circle is centred at (0,0) and that the radius is sqrt(r^2)