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(X-3)^2+(Y+6)^2=25
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circle centered at (3, -6) with radius r = 5 http://www.wolframalpha.com/input/?i=+%28x-3%29%5E2%2B%28y%2B6%29%5E2%3D25+
ok well u dont have to use wolfram for this its pretty simple. the equation of a cricle is x^2+y^2=r^2 So from this equation we know that the circle is centred at (0,0) and that the radius is sqrt(r^2)
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