Question

suppose to solve and round... very lost... do not know where to begin
4^X+1=5^x-1

Answer 1

\[4^{x+1}=5^{x-1}\]?

Answer 2

yes

Answer 3

take the log, get
\[(x+1)\ln(4)=(x-1)\ln(5)\] then a bunch of algebra to solve for x
remember that \(\ln(4)\) and \(\ln(5)\) are just numbers

Answer 4

got it ?