Question

Find lim x as approaches 0 sin(x)/(2x^2-x). Use only limits properties or sandwich theorem,since those are the only rules I have learnt so far;)

Answer 1

\[\LARGE \lim_{x\to 0}\frac{\sin (x)}{x}=?\]
this rule is equal to what? :)

Answer 2

\[\frac{\sin(x)}{2x^2-x}=\frac{\sin(x)}{x(2x-1)}=\frac{\sin(x)}{x}\frac{1}{2x-1}\]

Answer 3

I see

Answer 4

Thanks guys