Question

What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 29

Answer 1

lets find the common difference

an = a1 + d(n-1)

a6 = 4 + d(5) = 29; solve for d

Answer 2

once we know d, its just using the general formula again for n=32

a32 = a1 + d(32-1)

Answer 3

why are there 2 equal signs in the first equation ?

Answer 4

it means

a=b=c

which means

a=b
b=c
a=c

Answer 5

same as

1+3=4=5-1

Answer 6

1+3=4
4=5-1
5-1=1+3