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Mathematics 9 Online
OpenStudy (anonymous):

How do I go about reducing: (100+25pi)/(pi^2+8pi+16)

OpenStudy (anonymous):

\[100+25pi \over pi ^{2} +8pi +16\]

OpenStudy (dumbcow):

factor :)

OpenStudy (anonymous):

fully factor both the numerator and the denom

OpenStudy (dumbcow):

top has common factor of 25 bottom is a perfect square

OpenStudy (anonymous):

wowwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww hahah thanks

OpenStudy (anonymous):

Factor. \[25(4+pi)/(pi+4)(pi+4)\]

OpenStudy (anonymous):

right gotcha, thanks guys

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