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(2)/(x-3)-(1)/(x-1)
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\[\frac{2(x-1)}{(x-3)(x-1)}-\frac{x-3}{(x-1)(x-3)}\]
why did you put (x-1) next to the 2?
\[\frac{2x-2-x+3}{(x-3)(x-1)}=\frac{x+1}{(x-3)(x-1)}\]
to get a common denominator
Because to write a common denominator, I had to multiply both numerator and denominator by (x-1)
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sorry, i messed up look at mertsj's instead
Oh okay thanks
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