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Mathematics 8 Online
OpenStudy (anonymous):

(2)/(x-3)-(1)/(x-1)

OpenStudy (mertsj):

\[\frac{2(x-1)}{(x-3)(x-1)}-\frac{x-3}{(x-1)(x-3)}\]

OpenStudy (anonymous):

why did you put (x-1) next to the 2?

OpenStudy (mertsj):

\[\frac{2x-2-x+3}{(x-3)(x-1)}=\frac{x+1}{(x-3)(x-1)}\]

OpenStudy (anonymous):

to get a common denominator

OpenStudy (mertsj):

Because to write a common denominator, I had to multiply both numerator and denominator by (x-1)

OpenStudy (anonymous):

sorry, i messed up look at mertsj's instead

OpenStudy (anonymous):

Oh okay thanks

OpenStudy (mertsj):

|dw:1335915713168:dw|

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