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@DoomDude
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20Sin(70)= 18.79385
wait... that doesn't seem right
testingtutor, could you double check that?
20 cosec 70° ?
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ya, i think that is it
and turing...
The length 'opposite' is 20, what we are looking for is the hypotenuse
I was not trying to break the CoC, I thought I had explained it....
And we know that's a sine. \[\sin70 = \frac{20}{Hypotenuse}\]
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Hence, \[Hypotenuse = \frac{20}{sin70}\]
|dw:1335992360468:dw|\[\tan\theta=\frac ab\implies b=\frac a{\tan\theta}\]
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