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f(7) f(x)= 15,000x^.34 please help im so lost
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It looks like you just stick x=7 in and evaluate. f(x) is 15000 x^(.34) f(7) would be replacing x for 7
\[f(7)=(15,000)(7^{.34})\]
Are you studying logs?
If a numerical evaluation is required, use logs.
how do i do 7 to the .34th power?
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If you have studied logs then you would: .34 log 7 + log 15,000=.28733333 + 4.17609 =4.4634245 antilog 4.4634245 =29,068.63
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