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OpenStudy (anonymous):
What is the quotient: (3x2 + 8x - 3) ÷ (x + 3)
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OpenStudy (anonymous):
3x + 5, r = 1 3x - 5 3x + 1 3x - 1
OpenStudy (anonymous):
\[\frac{3x^2+8x-3}{x + 3}= \frac{(3x-1)(x+3)}{x + 3}\] The (x+3) terms cancel each other out, and you're left with \[3x-1\]
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