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Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of (–2, – 16), and x intercepts at x = –6 and x = 2. (Do not include the negative sign in your answer.) y = x2 + 4x − ___ just give me answer i hate this equation
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And, hint. your equation is in the form y=a(x-2)(x+6)
Find a by subsituting the point you already have.
also, vertex form y=a(x-h)^2+k
-2 xsquared?
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