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Help?? Anyone?? HELP Maybe?? A rocket is launched from atop a 102-foot cliff with an initial velocity of 158 ft/s. Substitute the values into the vertical motion formula h = –16t2 + vt + c. Let h = 0. Use the quadratic formula to find out how long after the rocket is launched it will hit the ground. Round to the nearest tenth of a second. Choices are 9.2s 0.6s 3.1s 10.5s
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for equations of the form\[ax^2+bx+c=0\] we have\[x={-b\pm\sqrt{b^2-4ac}\over2a}\]
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