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log base 2(x-1)+log base 2(x+1)=3, what is x and why. I get two different answers.
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write out that left side in terms of one log: logbase2 [(x-1)(x+1)] = 3 so now you can write this out in exponential form: 2^3 = (x-1)(x+1)
solve this quadratic..
this how you got your answer? and what are your answers?
one answer was 2 and the other answer was 3. I get when using your method
I get 3 using your method
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well, solving that quadratic yields two solutions but 1 of those solutions need to be thrown out because it is not a solution to the original equation. so there is only 1 solution.. x=3.
thank you.
yw... :)
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