Question

Can you help me find the values h, k, & p?

Answer 1

\[y^2+6y-x+16=0\]

Answer 2

then I got....

\[y^2+6y=x-16\]
\[y^2+6y+9=x-16+9\]
\[(y+3)^2=x-7\]

Answer 3

h=7
k=-3
P=????????

Answer 4

h=x value of the vertex
k=y value of vertex
and to find p=1/4