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Find the distance between the skew lines L1: x=y=z and L2: x+1=1/2y=1/3z
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we need a line that is perp to both of them, so cross their direction vectors is my first idea
what would be the parametric equation for line2?
these are formated such that t = .... line 1 x = y= z = t x = 0+t y = 0+t z = 0+t line2 x+1=1/2y=1/3z = t x+1 = t ; x = -1+t 1/2 y = t ; y = 0+2t 1/3 z = t ; z = 0+3t
thank you . i got it from here
youre welcome
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