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What is the solution set of 2x^2 - x < 15?
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start with \[2x^2-x-15<0\] then factor
once you find the zeros from factoring, you know you have a parabola that faces up, and so it will be negative between the zeros. can you factor this one?
um x / x <-5/2 or x > 3
hello?
hold on
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k!
\[(x-3) (2 x+5)\] so zeros are \(-\frac{5}{2}\) and 3
it is negative between the zeros, so \(-\frac{5}{2}<x<3\) is our solution
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