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Factor b12 + 8. (b4 - 2)(b16 + 2b4 + 4) (b4 + 2)(b8 - 2b4 + 4) (b4 - 2)(b8 + 2b4 + 4) (b4 + 2)(b16 - 2b4 + 4)
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the answer is (b4+2)(b8+2b4+4)
just multiply all the answer choices until one of them look like b12+8, if you cant remember how to factor a problem like this
b^12 + 8 is a sum of cubes (b^4)^3 + (2)^3 x^3 + x^3 = (x+y)(x^2 - x y + y^2)
it aint all plus
?
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(b^4 + 2)( b^8 - 2b^4 + 4) use the formula I gave.
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