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i forgot how to solve these, can someone teach me again? 2 2/5x 3 3/8
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Change both mixed numbers to improper fractions first.
What would that be?
12/5 and 27/8
Very good.
yay!
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\[\frac{12}{5}\times\frac{27}{8}\]
Now cancel a 4 from the 12 ands 8
\[\frac{3}{5}\times\frac{27}{2}\]
Now multiply numerators and denominators and change back to a mixed number.
wait im confused on the canceling part
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\[\frac{3}{5}\times\frac{27}{2}=\frac{81}{10}=8 \frac{1}{10}\]
|dw:1336008989985:dw|
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