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OpenStudy (anonymous):
what is the sum of 1/g+2 + 3/g+1
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OpenStudy (kropot72):
\[1/(g+2)+3/(g+1)=((g+1)+3(g+2))\div((g+2)(g+1))\] =\[(4g+7)\div((g+2)(g+1))\]
OpenStudy (anonymous):
So do you cross multiply then?
OpenStudy (kropot72):
The answer is: 4g + 7 ------------- (g + 2)(g + 1)
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