Question

4/30=e^(-0.1x)...solve for x

Answer 1

\[0.133=e ^{-0.1x}\]
\[\ln (0.133)=-0.1x\] is this correct?
then just divide both sides by -0.1 ??

Answer 2

yes

Answer 3

well that's what I was about to do too...
It looks good to me.
just fraction \(\frac{4}{30}=\frac{2}{15}\) would be easy if you'd use fractions...but for decimals is not needed :)

Answer 4

Thanks guys!

Answer 5

yw