Question

Find the quadratic function y=ax^2+bx+c whose graph passes through the given points.
(-2,-3), (1,12),(-3,12)

Answer 1

plug the points in the equation

first equation
-3=a(-2)^2+b(-2)+c
-3=4a-2b+c

second equation
12=a(1)^2+b(1)+c
12=a+b+c

third equation
12=a(-3)^2+b(-3)+c
12=9a-3b+c

now solve for the unkowns