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find the reference angle of the given angle: 150 degrees(more info in comments)
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here's the example from my textbook|dw:1336100046777:dw| it said \[A=1/2ab \sin \theta\] =1/2(10)(3)sin 120 = 15 sin 60 15\[\sqrt{3}/2\] (they multiplied) = about 13cm^2 but then i don't understand when the first problem says find the reference angle for the given angle
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