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\[x-1=\frac 1x\]
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\[x^2-x-1=0\]
?
golden ratio?
yeahs
it is not that hard to solve
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\[x=\frac{-(-1)\pm\sqrt{(-1)^2-4\times1\times(-1)}}{2\times(1)}\]
but why man... \(why\)? lol... it's friggin' everywhere
I like\[\huge\Phi={1\over{1+{1\over{1+{1\over{1+\ddots}}}}}}\]
\[x=\frac{1\pm\sqrt{5}}{2}\]
taking the inverse is the same as \[\varphi^{-1}=\varphi-1\] taking away 1
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